4[5x-4y(y-3)]=

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Solution for 4[5x-4y(y-3)]= equation:


Simplifying
4[5x + -4y(y + -3)] = 0

Reorder the terms:
4[5x + -4y(-3 + y)] = 0
4[5x + (-3 * -4y + y * -4y)] = 0
4[5x + (12y + -4y2)] = 0
[5x * 4 + 12y * 4 + -4y2 * 4] = 0
[20x + 48y + -16y2] = 0

Solving
20x + 48y + -16y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-48y' to each side of the equation.
20x + 48y + -48y + -16y2 = 0 + -48y

Combine like terms: 48y + -48y = 0
20x + 0 + -16y2 = 0 + -48y
20x + -16y2 = 0 + -48y
Remove the zero:
20x + -16y2 = -48y

Add '16y2' to each side of the equation.
20x + -16y2 + 16y2 = -48y + 16y2

Combine like terms: -16y2 + 16y2 = 0
20x + 0 = -48y + 16y2
20x = -48y + 16y2

Divide each side by '20'.
x = -2.4y + 0.8y2

Simplifying
x = -2.4y + 0.8y2

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